OpenSAML user discussion

[Jason Pedone <>]

All,

I'm trying to convert a base64 encoded SAML String
response into a SAMLResponse object, the code I am
executing to do so follows:

SAMLResponse obj_SAMLResponse = null;
if(str_SAMLResponse != null) {
 try {
   byte[] byte_arr_decodedBase64 = 
            Base64.decode(str_SAMLResponse);
   obj_SAMLResponse = new SAMLResponse(
        new
java.io.ByteArrayInputStream(byte_arr_decodedBase64));
   } catch (SAMLException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
   } catch (Base64DecodingException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
   }

I am getting the following exception:

[http-8080-Processor41] ERROR opensaml.SAMLObject
fromStream - caught an exception while parsing a
stream:
Content is not allowed in prolog.
org.xml.sax.SAXParseException: Content is not allowed
in prolog.
        at org.opensaml.SAMLObject.fromStream(Unknown Source)
        at org.opensaml.SAMLResponse.<init>(Unknown Source)

anyone have any ideas on what could cause this?  I
know the exception means that there are some
unexpected characters before the root node, however I
print out the unencoded xml before I encode it and
there is nothing preceeding the root node.  Its a
little hard to debug where I am decoding it b/c all I
have at that point is the base64 encoded SAML.

Thanks In Advance,

Jason P.


                
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